Two connected springs and potential energy as a function of x and y

[Diff.Ed]

Homework Statement

Two springs each of natural length a and spring constant C are connected at one end
(see figure). Consider a two dimensional displacement given by (x, y)
(a) Write the potential energy as a function of x and y.
(b) Find the force vector for a given (x, y) pair.

Homework Equations

Hooke's Law. Potential Energy.

The Attempt at a Solution

a) The stretch lengths of A and B springs Da and Db are
D_A = \sqrt{(a+x)^2 + y^2} - a
D_B = \sqrt{(a-x)^2 + y^2} - a
Since potential energy of a spring is
U_{spring} = 1/2kx^2
The total potential energy U can be written by
U(x,y) = U_A + U_B = C/2(D_A^2+D_B^2) = c/2((\sqrt{(a+x)^2 + y^2} - a)^2 + (\sqrt{(a-x)^2 + y^2} - a )^2)
b) \vec{F} = -\vec{\nabla} U and etc

Would you check my solution ? Is my answer correct ? Thanks for help in advance.

 

[genericusrnme]

looks right to me