Two-dimensional motion under Central Force

Eagletsam
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Homework Statement



Some students have just drawn my attention to the problem of particle motion under central force where the x and y coordinates are specified as functions of time, such as

x(t) = A [ kt – cos(βt) ]
y(t) = B [ 1 – sin(βt) ],

(here A, B, β and k are constants).




Homework Equations



The problem is to determine the radial and tangential orbital velocities (orbit assumed to be elliptical), and recover the canonical form of the equation (x2/a2 + y2/b2 = 1).
I have tried to figure this out for a few days without much success. Can anyone assist please?



The Attempt at a Solution



Express position vector r as

r = [x2 + y2]1/2
and evaluate dr/dt to obtain velocity as function of t. But this leads to messy calculation, which does not yield the angular and radial dependence.

Equally, attempt to eliminate t and obtain an equation in x and y proves quite hard.

We have also thought of coordinate transformation from (x,y,a,b) to (u,v,c,d) where u,v are velocity axes, but could not quite effect that.

 
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Since x(t) is unbounded, this doesn't look like a closed orbit. It's possible that this is a parabolic solution to a central force law, but you might want to verify that.
 
Thanks, very much, fzero, for early intervention.

I agree entirely that the orbit may not be elliptical!
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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