Two dimensional vectors question

  • Thread starter Thread starter neoncrazy101
  • Start date Start date
  • Tags Tags
    Vectors
AI Thread Summary
The discussion revolves around calculating the thickness of a magazine that a spider lands on after leaping off a table. The spider's initial velocity is 0.830 m/s at a 31.0° angle, and it takes 0.0640 seconds to land on the magazine. The user attempts to apply the vertical motion equation V0yT - 1/2gt² but struggles to achieve the correct thickness result. Another participant confirms the calculation yields a thickness of 0.0072576 m, indicating the original poster may be making a mistake with their calculator. The conversation highlights the importance of correctly applying equations in two-dimensional vector problems.
neoncrazy101
Messages
22
Reaction score
0
Hello, I'm having issues with a question like the following...


A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.830 m/s at an angle of 31.0° above the table, and it lands on the magazine 0.0640 s after leaving the table. Ignore air resistance. How thick is the magazine?


I just can't seem to figure out how to figure it. I've tried using V0yT -1/2gt2
With V0y = .830sin31 = .42748...
T = .0640s
and G = 9.8m/s2

But when I put it together I just can't seem to get the answer right. Am I using the wrong equation or what equation should I use? Any help with be much appreciated!
 
Physics news on Phys.org
your work looks correct. when i use your numbers i get:

thickness = 0.0072576 m

is this the result you are getting?
 
Hmmm. No it wasn't for some odd reason. I kept getting a much lower number for some reason... I'm probably doing something wrong with the calculator.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Handling two SHMs in different directions
Replies
18
Views
913
Boulder rolling off of cliff: will it hit the village?
Replies
16
Views
3K
Force problem with three masses and two pulleys
Replies
4
Views
2K
Vectors - Aircraft's velocity relative to ground
Replies
2
Views
1K
Confusion about the direction of the vectors: motional EMF
Replies
2
Views
2K
Two blocks connected by a string
Replies
2
Views
5K
Trouble dealing with vector coordinates in question
Replies
2
Views
951
Energy conservation for objects hanging from a pulley
Replies
6
Views
3K
Potential Energy - 2D inelastic collision - ballistic pendulum
Replies
10
Views
2K
How can simultaneous equations be used to solve two-dimensional motion problems?
Replies
5
Views
3K

Hot Threads

Recent Insights

Back
Top