- #1
jphillip
- 10
- 0
two blocks (2.2kg and 3.2kg) both hanging 1.80 m from the ground on a pulley(massless / frictionless) that is 4.80 m from the ground.
What is the maximum height the smaller block (2.2kg) reaches, when the system is released?
It appears that I need to find its velocity first of the system as the 3.2kg falls 1.8 m to the ground.
(3.2kg-2.2kg) / (3.2kg+2.2kg) = .185g * (9.8m/s2) = 1.81 m/s2
Then once the big block hits the ground, calc the additional height of the little block will rise additionally from the velocity created.
v2 - v2i / 2 (g)
1.812 / 2(9.8 m/s2) = .168 m + 1.8m (initial drop / increase)
Is this correct?
What is the maximum height the smaller block (2.2kg) reaches, when the system is released?
It appears that I need to find its velocity first of the system as the 3.2kg falls 1.8 m to the ground.
(3.2kg-2.2kg) / (3.2kg+2.2kg) = .185g * (9.8m/s2) = 1.81 m/s2
Then once the big block hits the ground, calc the additional height of the little block will rise additionally from the velocity created.
v2 - v2i / 2 (g)
1.812 / 2(9.8 m/s2) = .168 m + 1.8m (initial drop / increase)
Is this correct?