Two-Mass Spring System: Find Position of Second Mass as a Function of Time

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The discussion focuses on analyzing a two-mass spring system governed by Hooke's law, where both masses and springs have identical properties. Initially, the first mass is at x=1 and the second at x=2, but they are displaced to x=2 and x=7 at t=0. To find the position of the second mass as a function of time, users are advised to derive the equations of motion in the form of \ddot{x} = Kx, where K is a constant matrix. Reference to normal modes is emphasized, suggesting that textbooks on ordinary differential equations (ODEs) can provide further insights into solving the system. The discussion encourages a structured approach to modeling and solving the dynamics of the system.
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I have a system like this:

Wall-spring-mass-spring-mass

Both springs follow Hooks law with spring-constant k.
The masses are both m.

At rest, the first mass is at x=1 and the second at x=2

At t=0 the springs are pulled so that the first mass is at x=2 and the second at x=7.

Find the position of the second mass as a function of t.
 
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You have to use normal modes. Look that up in your textbook.
 
If you are having difficulty, your first step is to write the equations of motion for x1 and x2 to be of the form

\ddot{x} = Kx

where x is a vector containing x1 and x2 and K is a constant 2x2 matrix. If you don't know what to do from there, do what Meir Achuz suggested. A typical ODE book would also have explanation on how to solve such a system of equations.
 
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