Yes, that's the key. Hint: What will be the total displacement when the spring is compressed?guru1323 said:Since there are no external forces on the system, will the centre of mass of the system be at rest?
anigeo said:listen carefully.
since the two ends of the spring are connected to masses m1 and m2, hence you can consider the two halves of the string on either side of the centre of the string as two different springs connected to a fixed support (the centre).
each of the springs will have spring constant 2K(this can be obtained from some eqns.)
so you are right to think that the centre of mass of the system will be at rest.
however the is smt. wrong with the part of the question which says that the spring has an initial elongation X0.if it's so then X0 is the maxm. displacements of the block`
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Doc Al said:Yes, that's the key. Hint: What will be the total displacement when the spring is compressed?
Since there are no external forces acting, the acceleration of the COM must be zero. Assuming it was released from rest, the COM cannot move.guru1323 said:But i don't really understand the reason behind conclusion that COM will not move..I understand that acceleration of COM will be zero since there are no external forces present...but why can't we have a situation where COM moves with a constant velocity (acceleration = 0) till it comes to a maximum compression
Sounds good to me.I think sum of displacements of both blocks will be 2X0(Please correct me if i am wrong)
The displacement of each block depends on the ratio of their masses.anigeo said:moreover the maxm. displacement of each of the block will be X0.
Doc Al said:The displacement of each block depends on the ratio of their masses.
The concept of "Two masses attached to a spring" is a common scenario in physics where two objects are connected by a spring and can move back and forth due to the force of the spring.
Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. In the scenario of "Two masses attached to a spring", Hooke's Law explains the relationship between the force applied by the spring and the resulting displacement of the masses.
The motion of "Two masses attached to a spring" is affected by several factors, including the masses of the objects, the spring constant, and the amplitude of the oscillations (i.e. how far the objects are displaced from their equilibrium position).
The period of oscillation for "Two masses attached to a spring" can be calculated using the equation T = 2π√(m/k), where T is the period, m is the combined mass of the objects, and k is the spring constant.
Yes, "Two masses attached to a spring" can be used to model various real-world systems, such as pendulums, vibrating systems, and shock absorbers. This simple system can provide insights into more complex systems and their behavior.