Two Masses on Same String - Conical Pendulum

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A particle P, with a mass of 0.03 kg, is attached to a string and moves in a horizontal circle at an angular speed of 2 revolutions per second, resulting in a tension of 4.75 N and an angle x of 86.4 degrees. A second particle Q, with a mass of 0.02 kg, is connected to P, and both particles rotate in a vertical plane, with P moving in a circle of radius 0.75 m and Q in a circle of radius 1.5 m. The challenge lies in determining the tension in each string while maintaining constant angles to the vertical. The discussion highlights the complexities of analyzing the forces in a conical pendulum system. Further calculations and insights are needed to solve for the tensions in the strings for particle Q.
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3.(a) A particle P, of mass 0.03kg, is attached to one end of a light inextensible string OP, of length 1 m. The other end of the string is attached to a fixed point O. The particle moves in a horizontal circle, with centre vertically below O, at an angular speed of 2 revolutions per second. The string is inclined at a constant angle x to the vertical. Find both the tension in the string and the angle x.

I have done this using the conical pendulum method - x=86.4 degrees and T=4.75N

(b) A particle Q, of mass 0.02kg, is attached to one end of a second light inextensible string. The other end of this string is attached to P. The system rotates, with OP and PQ in a vertical plane that rotates about the vertical through O with constant angular speed. P moves in a horizontal circle of radius 0.75m and Q moves in a horizontal circle of radius 1.5m. The centres of both circles are vertically below O and the strings OP and PQ remain at constant angles to the vertical. Find the tension in each string.

NO IDEA about this one!
 
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