- #1

Matt

R1:

v0 = 0 m/s

T = unknown

x = o m

x0 = unknown

a = 9.8 m/s^2

R2:

v0 = 30 m/s

T = Time of R1 - 2 s

x = o m

x0 = unknown

a = 30 m/s @ 9.80 m/s^2

I know that these two equations must equal eachother:

(.5)(9.80 m/s^2)(T)^s = (30m/s)(T-2) + (.5)(9.80m/s^2)(T-2)^2

However, I have expanded this a million times and for some reason I can't get things to click. I mean, I could do guess and check but there has got to be an easier way...

The question asks how long it took the first stone to reach the gound, how high the building is, and what speeds the stones are at before they hit the ground.

Since they ask for the time first, I thought I would have to use the 2nd kinematic equation. But then I realized that I dont know what the initial height was. I feel stuck because I have these two variables the initial height and time. What do I use to find these one at a time? Lol, I'm stuck.