U Shaped Conductor w/ Rod & Magnetic Field

AI Thread Summary
The discussion revolves around a physics problem involving a U-shaped conductor at an angle in Earth's magnetic field. The first question addresses calculating the resistance needed for a conducting rod to slide at a constant speed of 20 m/s, using the provided equations. The second question explores the implications of reduced resistance on the rod's motion, suggesting that lower resistance would lead to lower electromotive force (EMF) and velocity. A clarification is made regarding the forces acting on the rod, emphasizing that only the component of weight along the rails balances the induced electromagnetic force. The angle of the rails is confirmed to be 50 degrees, which is crucial for accurate calculations.
ninjadrummer8
Messages
24
Reaction score
0

Homework Statement


Untitled.jpg


This is one of those problems with a U-Shaped Conductor, but this time it is at an angle and the Earth's Magnetic Field is perpindicular to the plane of it. The rails are 10m apart and the conducting rod weights 10 kg. No friction on the ramps, and the only resistance is in the resistor at the bottom.

Question 1: What is the value of the resistance if the rod slides with constant speed 20m/s?

Question 2: What would happen to the rod if the resistance was a lot less than what I found?


Homework Equations


F=(B^2)(L^2)V / R
F=ma


The Attempt at a Solution


Answer 1:
B=5x10^-5 T
L=10m
V=20m/s
F=ma=10(9.8)=98 N
So I can just plug those in and solve for R, correct? Or am I not able to use these equations in this case?

Answer 2:
Lower R would mean Lower EMF, which would also mean lower velocity, is this correct? So I think the rod would fall slower?
 
Physics news on Phys.org
ninjadrummer8 said:

Homework Equations


F=(B^2)(L^2)V / R
F=ma

The second equation is misleading. The acceleration of the system is zero, isn't it? The more appropriate equation is for weight: "w=mg." After learning and understanding General Relativity, you can go back to assuming they are the same equation, but in classical physics it is better to make the distinction between an accelerated object, and an object in a gravitational field.

Anyway, you analysis has only one flaw. The entire force of gravity is NOT balancing the electromagnetically induced force. Only the component of the weight along the direction of the rails can balance with this (The component of the weight perpendicular to the rails is balanced by the normal forces of the rails).

Is an angle, theta, assumed or given for this problem?
 
yes, you are right. I forgot to add that in my diagram. The angle between the rails and the ground is 50 degrees
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top