Uncertainty in Electron's Momentum in a 52 x 10-15 m Sphere

AI Thread Summary
To find the minimum uncertainty in an electron's momentum trapped in a sphere with a diameter of 52 x 10^-15 m, the uncertainty in position is equal to the diameter. The momentum uncertainty can be calculated using the Heisenberg Uncertainty Principle, specifically the formula p = h / d, where h is Planck's constant. The value of Planck's constant is approximately 6.626 x 10^-34 J·s. The setup of the equation is correct, confirming the application of the principle. This approach effectively determines the minimum uncertainty in the electron's momentum.
arod2812
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Homework Statement


an electron is trapped in a sphere whose diameter is 52 x 10-15 m. What is the minimum uncertainty in the electron's momentum?

Homework Equations


I know that the uncertainty in the electron's position is equal to the diameter... but how do I set up the equation?

The Attempt at a Solution


p = h / d. I plugged in 6.626E-34 for h and the diameter given. Is this correct?
 
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Yes, you're just using the Heisenberg Uncertainty Principle.
 

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