Liquidmoose
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A Wave packet is described by
\Psi(x)= sin \frac{kx}{x}
Make reasonable estimates of the uncertainty in position and wavevector and show that this function obeys the uncertainty priciple
\Deltax\Deltak>1
solutionish...
sin \frac{kx}{x} = sin (\pm\Deltax\Deltak) = 0
hence \Deltax must = some interger of \pi...?
this is about where i get lost don't know if I'm going in the right direction!?
\Psi(x)= sin \frac{kx}{x}
Make reasonable estimates of the uncertainty in position and wavevector and show that this function obeys the uncertainty priciple
\Deltax\Deltak>1
solutionish...
sin \frac{kx}{x} = sin (\pm\Deltax\Deltak) = 0
hence \Deltax must = some interger of \pi...?
this is about where i get lost don't know if I'm going in the right direction!?