Uncertainty principle and an electron

AI Thread Summary
The discussion focuses on applying the uncertainty principle to demonstrate that an electron confined within a nucleus of diameter 2 x 10^{-15} m must move at relativistic speeds, specifically greater than 0.1c. The user initially calculates the uncertainty in momentum using the relation ΔxΔp = ħ/2 and seeks guidance on how to derive the electron's speed from this. They consider substituting Δp with γmΔv but encounter difficulties due to the gamma factor. The conversation suggests exploring the relationship between γ and speed, indicating that if v exceeds 0.1c, then γ must also be greater than 1. Ultimately, the discussion emphasizes the need to find a way to express speed in terms of the uncertainty principle while considering relativistic effects.
thenewbosco
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question is:
use the uncertainty principle to show that if an electron were confined inside and atomic nucleus, diameter of 2 x 10^{-15}m, it would have to be moving relativistically i.e. more than 0.1c.
what i have done is the following:
\Delta x \Delta p = \frac{\hbar}{2}
then i set \Delta x = 2 x 10^{-15} and solved for \Delta p

from this i don't know how to solve for the speed, i considered replacing \Delta p with \gamma m\Delta v but this doesn't seem to work with the gamma in there.
what is a better way to solve this?
thanks
 
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Must you actually solve for the speed? [it can be done, since you can write \gamma in terms of v... but do you need to?]
While v>0.1c may characterize "relativistic", is there another way?
 
this was the hint that was given, that relativistic speeds were > 0.1c, but if you could give me a hint on comparing something else it would be appreciated.
 
What is the corresponding inequality for \gamma?
 
i don't know of anything similar, but gamma will be less than or equal to 1. is this close to the right track?
 
Find \frac{\gamma v}{c} (= \frac{\Delta p}{mc})

Squre both sides and solve for v/c.
 
gamma will be less than or equal to 1.

v < c
Therefore, gamma > 1
 
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