Uncertainty, volume, and measurement

Click For Summary

Homework Help Overview

The discussion revolves around calculating the percentage uncertainty in the volume of a sphere given a radius with a specified uncertainty. The original poster presents calculations for minimum, maximum, and nominal volumes based on a radius of 19.31, along with an uncertainty of ±0.13.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the definition of uncertainty and whether the given uncertainty should be considered absolute or relative. There are questions about the correctness of the original poster's calculations and the suggestion that calculus may be necessary for a more accurate approach.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the uncertainty calculation. Some guidance has been provided regarding the use of calculus and the appropriateness of the original method, but no consensus has been reached on the specific calculations or assumptions involved.

Contextual Notes

There is mention of significant figures in reporting uncertainty, and participants are considering how the "plus or minus" notation affects the calculations. The original poster expresses confusion about the use of calculus in this context.

mncyapntsi
Messages
38
Reaction score
4
Homework Statement
Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...
Relevant Equations
v=3pi/4r^3
I have done this question and gotten:

Vmin = 4pi/3(19.18)^3=29555.2
V = 4pi/3(19.31)^3=30160.3
Vmax = 4pi/3(19.44)^3=30773.5

Uncertainty: {[30773.5-29555.2]/30160.3}x100=4.04% however this is wrong...
Could someone please help me find out where I went wrong, or tell me if I went the wrong direction? I was told I should apparently be using calculus to solve this, but I have no clue where to even start...
Any help would be much much appreciated!

Have a wonderful day
 
Physics news on Phys.org
How is the uncertainty defined?
 
mncyapntsi said:
Homework Statement:: Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...
Does this amount to an absolute uncertainty of 0.13 or 0.26?
mncyapntsi said:
Uncertainty: {[30773.5-29555.2]/30160.3}x100=4.04%
You may or may not have received guidance about significant figures in reports of uncertainty. It is almost never appropriate to report uncertainty to more than two significant figures.
 
Last edited:
mncyapntsi said:
Homework Statement:: Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...
Relevant Equations:: v=3pi/4r^3

I have done this question and gotten:

Vmin = 4pi/3(19.18)^3=29555.2
V = 4pi/3(19.31)^3=30160.3
Vmax = 4pi/3(19.44)^3=30773.5

Uncertainty: {[30773.5-29555.2]/30160.3}x100=4.04% however this is wrong...
Could someone please help me find out where I went wrong, or tell me if I went the wrong direction? I was told I should apparently be using calculus to solve this, but I have no clue where to even start...
Any help would be much much appreciated!

Have a wonderful day
Have you taken calculus yet? Are you familiar with derivatives? Also, why do you think you are wrong?
 
mncyapntsi said:
Homework Statement:: Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...

I should apparently be using calculus to solve this
Note the "plus or minus". How does that compare with your answer of 4%?

You can use calculus. It leads to a useful general result about how small fractional errors in a linear dimension translate into fractional errors in two and three dimensions. But for the purpose of this question, your method is fine.
 
  • Like
Likes   Reactions: bob012345

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
23
Views
3K
Replies
18
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
958
Replies
15
Views
3K