Uncertainty, volume, and measurement

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SUMMARY

The discussion focuses on calculating the percentage uncertainty of the volume of a sphere with a radius of 19.31 cm, given a measurement uncertainty of ±0.13 cm. The user initially calculated the minimum and maximum volumes using the formula V = (4/3)πr³, resulting in Vmin = 29555.2 cm³, V = 30160.3 cm³, and Vmax = 30773.5 cm³. The calculated percentage uncertainty was 4.04%, which was deemed incorrect. Participants suggested that calculus could provide a more accurate method for determining uncertainty, emphasizing the importance of understanding derivatives in this context.

PREREQUISITES
  • Understanding of volume calculations for spheres using the formula V = (4/3)πr³
  • Basic knowledge of percentage calculations
  • Familiarity with the concept of uncertainty in measurements
  • Introduction to calculus, specifically derivatives
NEXT STEPS
  • Learn how to apply calculus to derive the formula for uncertainty in volume measurements
  • Study the concept of significant figures in reporting uncertainties
  • Explore the relationship between linear dimensions and their impact on volume uncertainty
  • Practice calculating percentage uncertainties with various geometric shapes
USEFUL FOR

Students in physics or engineering, educators teaching measurement and uncertainty, and anyone seeking to improve their understanding of calculus applications in real-world scenarios.

mncyapntsi
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Homework Statement
Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...
Relevant Equations
v=3pi/4r^3
I have done this question and gotten:

Vmin = 4pi/3(19.18)^3=29555.2
V = 4pi/3(19.31)^3=30160.3
Vmax = 4pi/3(19.44)^3=30773.5

Uncertainty: {[30773.5-29555.2]/30160.3}x100=4.04% however this is wrong...
Could someone please help me find out where I went wrong, or tell me if I went the wrong direction? I was told I should apparently be using calculus to solve this, but I have no clue where to even start...
Any help would be much much appreciated!

Have a wonderful day
 
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How is the uncertainty defined?
 
mncyapntsi said:
Homework Statement:: Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...
Does this amount to an absolute uncertainty of 0.13 or 0.26?
mncyapntsi said:
Uncertainty: {[30773.5-29555.2]/30160.3}x100=4.04%
You may or may not have received guidance about significant figures in reports of uncertainty. It is almost never appropriate to report uncertainty to more than two significant figures.
 
Last edited:
mncyapntsi said:
Homework Statement:: Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...
Relevant Equations:: v=3pi/4r^3

I have done this question and gotten:

Vmin = 4pi/3(19.18)^3=29555.2
V = 4pi/3(19.31)^3=30160.3
Vmax = 4pi/3(19.44)^3=30773.5

Uncertainty: {[30773.5-29555.2]/30160.3}x100=4.04% however this is wrong...
Could someone please help me find out where I went wrong, or tell me if I went the wrong direction? I was told I should apparently be using calculus to solve this, but I have no clue where to even start...
Any help would be much much appreciated!

Have a wonderful day
Have you taken calculus yet? Are you familiar with derivatives? Also, why do you think you are wrong?
 
mncyapntsi said:
Homework Statement:: Find the % uncertainty of the V of a sphere with r = 19.31 plus or minus 0.13...

I should apparently be using calculus to solve this
Note the "plus or minus". How does that compare with your answer of 4%?

You can use calculus. It leads to a useful general result about how small fractional errors in a linear dimension translate into fractional errors in two and three dimensions. But for the purpose of this question, your method is fine.
 
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