Uncovering the Shortest Wavelength of Be3+ Lines

[MrDMD83]

Homework Statement

Doubly ionized lithium Li2+ (Z = 3) and triply ionized beryllium Be3+ (Z = 4) each emit a line spectrum. For a certain series of lines in the lithium spectrum, the shortest wavelength is 1979.8 nm. For the same series of lines in the beryllium spectrum, what is the shortest wavelength?

Homework Equations

The Attempt at a Solution

none

 

[chaoseverlasting]

Hehe... give it a shot man. Tell you what, the equation you need is:

\frac{1}{\lambda}=Rz^2(\frac{1}{n_1^2}-\frac{1}{n_2^2})

where R is the rydberg constant, z is the atomic number, and n2 is the shell it jumps from to n1 (the final shell)