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Under Gravity

  1. Mar 6, 2006 #1
    A stone is droped from the top of a cliff of height 256 feet, and, at the same instant, another stone is projected vertically upwards from the ground with a speed of 96 ft/s. Find where they will meet?
    I have the following:
    v1=u1+at, v2=u2+at, s1=u1t+1/2at^2, s2=u2+1/2at^2,
    I also have: v1^2=u1^2+2as1 and V2^2=u2^2+2as2
    The question is what do I do next, please?
  2. jcsd
  3. Mar 6, 2006 #2


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    You have the inital velocity and acceleration of both. You also know that the distance the stone thrown upwards from the ground has travelled when they meet is [itex]256-s[/itex] where [itex]s[/itex] is the distance travelled by the dropped stone.
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