# Under Gravity

1. Mar 6, 2006

### John O' Meara

A stone is droped from the top of a cliff of height 256 feet, and, at the same instant, another stone is projected vertically upwards from the ground with a speed of 96 ft/s. Find where they will meet?
I have the following:
v1=u1+at, v2=u2+at, s1=u1t+1/2at^2, s2=u2+1/2at^2,
I also have: v1^2=u1^2+2as1 and V2^2=u2^2+2as2
The question is what do I do next, please?

2. Mar 6, 2006

### Hootenanny

Staff Emeritus
You have the inital velocity and acceleration of both. You also know that the distance the stone thrown upwards from the ground has travelled when they meet is $256-s$ where $s$ is the distance travelled by the dropped stone.