Understand F_0 & Omega in Driven Oscillators

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F_0 represents the amplitude of the sinusoidal forcing function in driven oscillators, and it has dimensions of force, typically measured in Newtons. The equation f(t) = F_0 cos(ωt) illustrates that while ω is the frequency of the forcing function, it is also associated with the damped natural frequency of the system. The distinction between initial and final omega arises from the system's response to the driving force, where the frequency can change over time due to damping effects. The discussion clarifies that F_0 is not a distance measurement but rather a force that drives the oscillation. Understanding these parameters is crucial for analyzing the behavior of driven oscillators effectively.
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I found this equation for driven oscillators, and am unsure what the F_0 means, and how it's used. Can someone please briefly explain this?
Also, I don't get what the difference is between the initial and final omega. (how can there be a final omega if it's constantly increasing?)
 

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##F_0## is the amplitude of a sinusoidal forcing function, ##\omega_0## is the undamped natural frequency of the system, and ##\omega## is the frequency of the forcing function, which looks something like ##f(t)=f_0\sin(\omega t)## or ##f(t)=f_0\cos(\omega t)##.

The definition of ##\omega## shown is also the damped natural frequency of the system.
 
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So are the units for F_0 meters? (So it's not a force?)
Thanks.
 
##F_0## has dimensions of force. You can easily see this by looking at the dimension of each part of the expression. Consider f(t)=f_0 \cos(\omega t). The dimension of ##t## is of course time, and the dimension of ##\omega## must be angle/time so that ##\omega t## has dimensions of an angle (e.g. radians). This must be so, as, for example, what is the cosine of a second? It's meaningless. Since ##f(t)## is a force, and ##\cos(\omega t)## is dimensionless, it must be that ##f_0## has the dimensions of force, e.g. Newtons for SI.
 
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