Understand Laplace alot better now

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Homework Help Overview

The discussion revolves around the Laplace transform, specifically addressing the inclusion of a function, x(t), in the transformation of a product involving t^2 and sin(3t). Participants are exploring the nuances of applying the Laplace transform to functions that include unit step functions, u(t).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question whether x(t) should be included in the Laplace transformation of g(t) and discuss the treatment of unit step functions in similar problems.

Discussion Status

Some participants have provided insights into the treatment of unit step functions and their implications for the Laplace transform. There is an ongoing exploration of how to approach the transformation of the specific function g(t) involving multiple terms.

Contextual Notes

There is mention of needing to review relevant chapters on step functions and Laplace transforms, indicating potential gaps in understanding. The discussion also hints at the complexity introduced by convolution integrals.

mathrocks
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Ok, I'm starting to understand Laplace a lot better now. But I have, hopefully, my last question. If you have a function like

g(t)=t^2 * sin(3t) * x(t) where x(t) has an already defined laplace transform.

do you actually include x(t) in your laplace transformation? Because when I see other problems that have u(t) at the end you don't really do anything with them, you only worry about the terms in front of it. Like f(t)=sin(3t)u(t), the answer is simply 3 / (s^2 + 9)...u(t) is not included in it.
 
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mathrocks said:
g(t)=t^2 * sin(3t) * x(t) where x(t) has an already defined laplace transform.

do you actually include x(t) in your laplace transformation?

Yes, you do.

Because when I see other problems that have u(t) at the end you don't really do anything with them, you only worry about the terms in front of it. Like f(t)=sin(3t)u(t), the answer is simply 3 / (s^2 + 9)...u(t) is not included in it.

That's because u(t)=1 over the entire range of integration in the transform. If you had instead u(t-a), a>0, then you could not just drop it.
 
Tom Mattson said:
That's because u(t)=1 over the entire range of integration in the transform. If you had instead u(t-a), a>0, then you could not just drop it.


So for the problem:
g(t)=t^2 * sin(3t) * x(t)

How would you go about transforming that? This is my first encounter of 3 terms...
 
yeah, you'll probably need to review the chapter the step functions/laplace.

By the way, ever heard of convolution integrals?
 

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