Understanding Absolute Value Sign in Derivative

AI Thread Summary
The discussion revolves around the confusion regarding the absolute value sign in the derivative expression [x-1/|x-1|]e^x + |x-1|e^x. It clarifies that when setting the derivative to zero, two cases arise: one for x greater than or equal to 1, and another for x less than 1, effectively removing the absolute value signs. The function can be expressed as y(x) = (x-1)e^x for x ≥ 1 and y(x) = -(x-1)e^x for x < 1. The derivative will represent two distinct functions and is undefined at x = 1. Plotting the conditional function helps visualize these behaviors.
sony
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Hi

So I am a little confused about the absolute value sign here. Is the derivative right:

[x-1/|x-1|]e^x + |x-1|e^x

But what do I do when I set this to zero? Do I get two expressions, one for x>1 and one for x<1 ? (thus removing the absolute value signs)
 
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Hints anyone...?
 
|x-1|=x-1\quad\text{for}\quad x\geq 1

and:

|x-1|=-(x-1)\quad\text{for}\quad x&lt;1

Thus your expression represents this function:

y(x)=<br /> \left\{<br /> \begin{array}{rcl}<br /> (x-1)e^x &amp; \mbox{for} &amp; x\geq 1 \\ <br /> -(x-1)e^x &amp; \mbox{for} &amp; x&lt;1<br /> \end{array}\right.<br />

and so the derivative will represent two functions likewise but will not exist at x=1. Try plotting this conditional function and you'll see what I mean.
 
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