Understanding Boundedness in Real Sequences

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Homework Statement



Let \ell_\infty \mathbb({R}) be the set of bounded real sequences with k > 0 such that \left | x_n \right |\le k

a) (n)=(1,2,3...) \notin \ell_\infty \mathbb({R}). This is not bounded 'above'?

b) (2n^2+1) \notin \ell_\infty \mathbb({R}) Same answer as above?

c) (1/n)=(1,1/2,1/3,1/4...) \in \ell_\infty \mathbb({R}) Is bounded above?

d) (4-1/n) \notin \ell_\infty \mathbb({R}) Why is this not bounded? Is it because the value wll not go below 0?
 
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a) yes.

b) yes.

c) bounded above AND below: 0 < 1/n ≤ 1

d) i think there's a typo here
 


bugatti79 said:

Homework Statement



Let \ell_\infty \mathbb({R}) be the set of bounded real sequences with k > 0 such that \left | x_n \right |\le k

a) (n)=(1,2,3...) \notin \ell_\infty \mathbb({R}). This is not bounded 'above'?
Correct. No matter how large an M you pick, for some n, an > M.
bugatti79 said:
b) (2n^2+1) \notin \ell_\infty \mathbb({R}) Same answer as above?
Yes.
bugatti79 said:
c) (1/n)=(1,1/2,1/3,1/4...) \in \ell_\infty \mathbb({R}) Is bounded above?
Yes, by 1.
bugatti79 said:
d) (4-1/n) \notin \ell_\infty \mathbb({R}) Why is this not bounded? Is it because the value wll not go below 0?
Looks bounded to me. Every number in the sequence is less than 4. Why do you think it's not bounded?
 


Mark44 said:
Looks bounded to me. Every number in the sequence is less than 4. Why do you think it's not bounded?

Thanks guys,

Is d) bounded above AND below...because 0&lt;(4-1/n) \le 4...?
 


For d, you have 3 <= 4 - 1/n < 4, with n being a positive integer.
 


Thanks Mark.
 
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