Understanding Buoyancy: Calculating Mass of a Ship in Different Fluids

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A ship experiences a change in buoyancy when transitioning from seawater to freshwater, sinking slightly due to the difference in specific gravity. When a 600,000-kg load is removed, the ship returns to its original waterline, indicating that the mass of the ship can be calculated based on buoyancy principles. The discussion highlights confusion regarding volume changes when the load is removed, but it emphasizes that the ship's buoyancy is determined by its weight and the displaced water volume. Archimedes' principle is referenced to clarify that the ship rises because it is now lighter. Understanding these concepts is crucial for accurately calculating the mass of the ship before unloading.
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53 ••• [SSM] A ship sails from seawater (specific gravity 1.025) into
freshwater, and therefore sinks slightly. When its 600,000-kg load is removed, it
returns to its original level. Assuming that the sides of the ship are vertical at the
water line, find the mass of the ship before it was unloaded.

I'm afraid I have a horrible problem about my conception of volume.

I have solved for the sum of forces in the Y component in both cases. For water and sea water.
My solutions manual shows that one can solve for Vg in water and replace it in the sea water equation. I can't conceive, how this is possible, because a load is taken of the boat when it's in water. Shouldn't the volume change as well? There's more room in the boat.

Thank you.
 
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The boat rises because it is lighter by 600,000 kg. Remember what Archimedes said about floating objects.
 
True.

Thank you.
 
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