Understanding Capacitor Voltage in Series Circuits

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In series circuits, the total voltage is distributed among the capacitors, meaning each capacitor experiences a different voltage. The voltage across an individual capacitor can be calculated using the formula Q = C V, where Q is the charge, C is the capacitance, and V is the voltage across that specific capacitor. For three capacitors in series with a total of 12 volts, the voltage across the 2 uF capacitor will not equal 12 volts. Instead, it will be a fraction of the total voltage based on the capacitance values of all capacitors in the series. Understanding this distribution is crucial for accurately calculating voltage across each capacitor.
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Problem is in paint doc...

My solution: Multiply 2.0*10^-6 by 12 volts... what am I doing wrong?
 

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For a capacitor Q = C V, but V would be the voltage on the individual capacitor.

There would be 12 volts across the three capacitors in series. The 2 uF capacitor would have a voltage different than 12 V.
 
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