Understanding Convolution Integral Changes and the Effect on H Function

nhrock3
Messages
403
Reaction score
0
5fqj5l.jpg

cant understand the red arrow transition
i changes the intervals and i cuts half of the arguent inside the integral
i can't see why
?

regarding the interval change
the H function is 1 in a certain interval
so if they change the integrval then its no longer H inside
because we have taken the '1' part of the H
??

regarding the cutting in half the argument inside the integral
i have no idea
 
Physics news on Phys.org
On the interval 0 <= t <= 1, we have H(t+1) - H(t-1) = 1. Outside that interval, H(t+1) - H(t-1) = 0. The steps the author skips here are just simplifying steps. Can you get the rest from here? I hope this helps.
 
thanks
:)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top