Understanding Cylindrical Vector Fields: Can They Be Electrostatic?

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The discussion focuses on whether the given cylindrical vector field F can represent an electrostatic field. It is established that an electrostatic field must be curl-less, which can be verified by calculating the curl of F. If the curl is zero, it indicates that the field can be expressed as a gradient of a scalar potential, confirming its electrostatic nature. The conversation highlights the importance of understanding the relationship between curl and electrostatic fields. Overall, the key takeaway is that checking the curl is essential to determine if the vector field is electrostatic.
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I'm given this:

A vector field is given in cylindrical coordinates as:

F=(A)(s)(PhiHat) + (B)(z)(zhat)

Where A and B are constants. Could F be an electrostatic field ? Why or why not ?

I kind of feel stupid asking this because I feel like I should know, but, I'm currently braindead after having just spent hours doing the previous 29 problems.

Thanks,
Dan
 
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taishar said:
I'm given this:

A vector field is given in cylindrical coordinates as:

F=(A)(s)(PhiHat) + (B)(z)(zhat)

Where A and B are constants. Could F be an electrostatic field ? Why or why not ?

I kind of feel stupid asking this because I feel like I should know, but, I'm currently braindead after having just spent hours doing the previous 29 problems.

Thanks,
Dan


an electrostatic field should be curl-less.

so... take the curl and see if it's zero or not.
 
i guess i should provide some justification for my answer so that you'll believe me! :-p

an electrostatic field can be written in terms of a scalar potential:

<br /> \mathbf{E} = -\nabla V.<br />


and it is a mathematical fact that
<br /> \nabla \times \nabla V = 0<br />

for any V.


So if the curl is strictly zero, this implies that E can be expressed in terms of a scalar potential (and not have a vector potential term), and this is enough to determine if E is a static field or not.
 
Duh. I knew I was just being stupid. I had to do a couple similar problems earlier. Gah. Thanks a bunch :) Too many hours doing homework...
 
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