Understanding Eigenfunctions and Eigenvalues in Quantum Mechanics

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SUMMARY

The discussion centers on the mathematical demonstration of eigenfunctions and eigenvalues in quantum mechanics, specifically using the Hamiltonian operator defined as H = -ħ²/(2m) d²/dx². The function φ(x) = A sin(2x) + B cos(2x) is confirmed to be an eigenfunction of this operator, with the corresponding eigenvalue being 2ħ²/m. Participants emphasize the importance of taking the second derivative of the function and applying the Hamiltonian operator to verify the eigenvalue relationship.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with the Hamiltonian operator
  • Knowledge of eigenfunctions and eigenvalues
  • Basic calculus, specifically differentiation
NEXT STEPS
  • Study the derivation of eigenvalues using the Hamiltonian operator
  • Learn about the implications of eigenfunctions in quantum mechanics
  • Explore the mathematical formulation of quantum mechanics using TeX
  • Investigate other examples of eigenfunctions in different quantum systems
USEFUL FOR

Quantum chemistry students, physicists, and anyone studying quantum mechanics who seeks to deepen their understanding of eigenfunctions and eigenvalues in relation to the Hamiltonian operator.

samdiah
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I am a seond year Quantum Chemistry student. I am having a hard time understanding these concepts. I was wondering I can get help in this concept.

How can it be demonstrate mathematically in the Hamiltonian operator that the function
φ(x) = A sin(2x) + B cos(2x)

is an eigenfunction of the Hamiltonian operator:
H=-h^2 d^2
2m dx^2

What is the eigenvalue equal to?
 
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samdiah said:
I am a seond year Quantum Chemistry student. I am having a hard time understanding these concepts. I was wondering I can get help in this concept.

How can it be demonstrate mathematically in the Hamiltonian operator that the function
φ(x) = A sin(2x) + B cos(2x)

is an eigenfunction of the Hamiltonian operator:
H=-h^2 d^2
2m dx^2

What is the eigenvalue equal to?

Yikes. That is very difficult to read. You should try and learn some TeX. It is good for the soul, and for the typesetting. for example:

<br /> H=-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\;.<br />

I believe that If you click on the above equation it will show you the TeX source that I used to write the equation in such a pretty manner.

Anyways. In order to do what you want you need to take the derivative of
<br /> A\sin(2 x)+B\cos(2 x)<br />
twice.

what do you get?

Then multiply by
<br /> -\frac{\hbar^2}{2m}\;.<br />

That is what the symbols on the right hand side of the equation for H are instructing you to do.

What is the end result?

Is it proportional to
<br /> A\sin(2 x)+B\cos(2 x)<br />
?

What is the proportionality constant?
 
In case you are not aware of eigenfunctions:
http://mathworld.wolfram.com/Eigenvalue.html"
 
Last edited by a moderator:
I found the two derivatives and I found that the function φ(x) = A sin(2x) + B cos(2x)
is an eigenfunction of the Hamiltonian operator:

H=-h2 d2
2m dx2

and the proportionality constant is
2h2
m

Can someone confirm with me if this is right or what did I do wrong?

Thanks so much for all the help.
 
Yes, you have the correct eigenvalue (proportionality constant).
 

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