Understanding Eigenfunctions and Eigenvalues in Quantum Mechanics

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Homework Help Overview

The discussion revolves around understanding eigenfunctions and eigenvalues in the context of quantum mechanics, specifically relating to the Hamiltonian operator and a given function φ(x) = A sin(2x) + B cos(2x).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the mathematical demonstration of the function being an eigenfunction of the Hamiltonian operator. Questions arise about the process of taking derivatives and determining the eigenvalue.

Discussion Status

Some participants have provided guidance on the steps needed to verify the eigenfunction status and the proportionality constant. There is acknowledgment of correct findings, but no explicit consensus on the overall understanding of the concepts.

Contextual Notes

There are indications of confusion regarding the notation and mathematical representation, as well as a reference to the use of TeX for clarity in mathematical expressions.

samdiah
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I am a seond year Quantum Chemistry student. I am having a hard time understanding these concepts. I was wondering I can get help in this concept.

How can it be demonstrate mathematically in the Hamiltonian operator that the function
φ(x) = A sin(2x) + B cos(2x)

is an eigenfunction of the Hamiltonian operator:
H=-h^2 d^2
2m dx^2

What is the eigenvalue equal to?
 
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samdiah said:
I am a seond year Quantum Chemistry student. I am having a hard time understanding these concepts. I was wondering I can get help in this concept.

How can it be demonstrate mathematically in the Hamiltonian operator that the function
φ(x) = A sin(2x) + B cos(2x)

is an eigenfunction of the Hamiltonian operator:
H=-h^2 d^2
2m dx^2

What is the eigenvalue equal to?

Yikes. That is very difficult to read. You should try and learn some TeX. It is good for the soul, and for the typesetting. for example:

<br /> H=-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\;.<br />

I believe that If you click on the above equation it will show you the TeX source that I used to write the equation in such a pretty manner.

Anyways. In order to do what you want you need to take the derivative of
<br /> A\sin(2 x)+B\cos(2 x)<br />
twice.

what do you get?

Then multiply by
<br /> -\frac{\hbar^2}{2m}\;.<br />

That is what the symbols on the right hand side of the equation for H are instructing you to do.

What is the end result?

Is it proportional to
<br /> A\sin(2 x)+B\cos(2 x)<br />
?

What is the proportionality constant?
 
In case you are not aware of eigenfunctions:
http://mathworld.wolfram.com/Eigenvalue.html"
 
Last edited by a moderator:
I found the two derivatives and I found that the function φ(x) = A sin(2x) + B cos(2x)
is an eigenfunction of the Hamiltonian operator:

H=-h2 d2
2m dx2

and the proportionality constant is
2h2
m

Can someone confirm with me if this is right or what did I do wrong?

Thanks so much for all the help.
 
Yes, you have the correct eigenvalue (proportionality constant).
 

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