Understanding Integration by Substitution

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Homework Help Overview

The discussion revolves around the topic of integration by substitution, specifically focusing on the transformation of variables in integrals and the implications of changing bounds during substitution.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the substitution of variables, with suggestions to let \( u = 5 \ln x \) or \( u = \ln x \). Questions arise regarding the transformation of integral bounds and whether further substitutions are necessary.

Discussion Status

There is an ongoing exploration of the substitution method, with some participants providing partial guidance. The original poster and others are questioning the implications of their substitutions and the resulting bounds of integration, indicating a productive dialogue without a clear consensus.

Contextual Notes

Participants express uncertainty about the transformation of bounds when substituting variables in integrals, and there is mention of homework constraints that may limit the depth of discussion.

jisbon
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Homework Statement
$$\int ^{10}_{0}f\left( x\right) dx=25$$
Find the value of
$$\int ^{e^{2}}_{1}\dfrac {f\left( 5\times \ln \left( x\right) \right) }{x}dx$$
Relevant Equations
-
Not sure how do I start from here, but do I let $$u = lnx$$ and substitute?
Cheers
 
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Yes, let ##u = 5\ln x##. Then ##du = \frac{5}{x} dx \implies \frac{du}{5} = \frac{1}{x}dx## and your integral becomes

$$\frac{1}{5}\int_0^{10} f(u) du$$

Can you conclude?
 
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Math_QED said:
Yes, let ##u = 5\ln x##. Then ##du = \frac{5}{x} dx \implies \frac{du}{5} = \frac{1}{x}dx## and your integral becomes

$$\frac{1}{5}\int_0^{10} f(u) du$$

Can you conclude?
$$\frac{1}{5}\int_0^{10} f(u) du$$

Since I'm trying to find from 1 to $$e^2$$ instead of 0 to 10, do I do another substitution?
 
Can I say that $$1/5 *\int ^{10}_{0}f\left( x\right) dx=5$$ too?
 
Math_QED said:
Yes, let ##u = 5\ln x##. Then ##du = \frac{5}{x} dx \implies \frac{du}{5} = \frac{1}{x}dx## and your integral becomes

$$\frac{1}{5}\int_0^{10} f(u) du$$

Can you conclude?
I think that is giving too much away. That is 90% of the work.
 
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PeroK said:
I think that is giving too much away. That is 90% of the work.

Yes you may be right, the OP thought of the subsitution ##u = \ln x ## so at least he thought about the question a bit.
 
jisbon said:
Can I say that $$1/5 *\int ^{10}_{0}f\left( x\right) dx=5$$ too?
Are you asking if ##25/5 = 5##?
 
jisbon said:
$$\frac{1}{5}\int_0^{10} f(u) du$$

Since I'm trying to find from 1 to $$e^2$$ instead of 0 to 10, do I do another substitution?

Please reread my reply:

$$\int_1^{e^2} \dots dx = \int_{0}^{10}\dots du$$ after substitution ##u = 5 \ln x## (the bounds of the integral transform by the subsitution).
 
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Sorry, I didn't understand why the bounds of the integral were transformed earlier on. All is good now, thanks all for your help
 

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