Understanding Joule Expansion and Its Implications on (dT/dV) const U = 0

  • Thread starter Thread starter bon
  • Start date Start date
  • Tags Tags
    Thermal
AI Thread Summary
The discussion revolves around the Joule expansion experiment, which demonstrates that the change in temperature with respect to volume at constant internal energy (dT/dV) is zero. This conclusion stems from the first law of thermodynamics, indicating that for an ideal gas, internal energy is a function of temperature alone. The participants express confusion about deriving the relationship between (dT/dV) and the equation of state, specifically how it leads to the ideal gas law (pV = RT). Clarification is sought on the implications of these equations and their interconnections. Understanding these principles is crucial for grasping the behavior of ideal gases under Joule expansion conditions.
bon
Messages
547
Reaction score
0

Homework Statement



\"Explain why the joule expansion experiment implies that (dT/dV) const U = 0\"


Homework Equations





The Attempt at a Solution



So I\'m not sure how to do this!

Using 1st law we can say that at const U Tds = pdV, but not sure how to get what they want..
 
Physics news on Phys.org
Ok so i guess you can just say that U = U(T) for an ideal gas...then the result follows.

The next part asks me to show that that equation i.e. (dT/dV) const U = 0 and the equation PV = k(T) --i.e. pV = some function of T, together imply the equation of state is pV = RT where R is some constant of proportionality..

How is this meant to work? Thanks.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top