Understanding Kirchhoff's Circuit Problem: Finding Currents in a Complex Circuit

  • Thread starter Thread starter Boulderbison19
  • Start date Start date
  • Tags Tags
    Circuit
AI Thread Summary
The discussion centers on solving Kirchhoff's Circuit Problem to find the currents through resistors r1 and r2. The user successfully calculated the current through r2 as -0.4 Amps using the equation V=IR, but expressed uncertainty about their method. Guidance was provided on applying Kirchhoff's Laws, emphasizing the need to sum currents at nodes and voltages around loops to derive equations for I1 and I2. The conversation highlights the importance of correctly identifying circuit paths to solve for the currents. Overall, the exchange illustrates collaborative problem-solving in understanding complex circuit analysis.
Boulderbison19
Messages
7
Reaction score
0

Homework Statement


Determine the magnitude and directions of the currents through r1 and r2 in the diagram below.


Homework Equations


V=IR

here is the schematic, i hope you can get the idea of the circuit from it:
kirchoffs.jpg




The Attempt at a Solution



so i found the current through r2 to be -.4 Amps, which was the answer given using:

V=IR
6.0=15I

but i don't know if i just got lucky.

the answers given were I1=.68 amps and I2= -.4 amps. i am completely stuck on all of these kirchhoffs circuit problems, so any help will be much apreciated!
 
Physics news on Phys.org
Kirchoff's Laws require you to sum the currents into each node or sum the voltages around each loop. To do the voltage law, call I1 the current circulating, say, CW around the top loop (9V battery, R1, R2, back to battery) and I2 the current circulating around the bottom loop. The voltages around the top loop are

-9 + 22*I1 + 15*(I1-I2) =0

Do you see how that works? Now you do the bottom loop. Then it is a simple matter to solve for the currents I1 and I2.

BTW, are you at CU? Just wondering from your screen name...
 
thanks so much! that makes a lot more sense now. i couldn't figure out the paths, and tried almost everything.

i am at boulder high, just down the street.
 
Good, glad to help :biggrin:

I'm south nearer Fairview.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top