Understanding Metric Connection and Geodesic Equations in General Relativity"

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Homework Help Overview

The discussion revolves around calculating the geodesic equation in cylindrical coordinates within the context of General Relativity, specifically focusing on the use of the metric connection and the associated indices.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the calculation of the geodesic equation and expresses confusion regarding the metric connection and the role of indices. Participants discuss the nature of dummy indices and the total number of gamma coefficients that can arise in this context.

Discussion Status

The discussion has seen some progress, with the original poster indicating a moment of clarity regarding the problem. However, there remains an exploration of the metric in the specified coordinates and the implications of the calculations.

Contextual Notes

Participants note that some gamma coefficients may equal zero or be redundant, indicating a need for careful consideration of the metric tensor in cylindrical coordinates.

Mr-R
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Dear all,

In my journey through learning General relativity. I have stumbled upon this problem. I have to calculate the geodesic equation for R^{3} in cylindrical polars. I am not sure how to use the metric connection. The indices confuse me. I would appreciate it if someone could shade some light on it. Every time I try to calculate it I get zero, sometimes due to the first metric tensor and sometime the terms in the parentheses are zeros.

\Gamma_{bc}^{a}=\frac{1}{2}g^{ad}(\partial_{b}g_{dc}+\partial_{c}g_{db}-\partial_{d}g_{bc})

As I understand it, the index d is the dummy index and runs from 1 to 3 in this case, right? What about b and c? how do I use them?

Thanks in advance
 
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Mr-R said:
As I understand it, the index d is the dummy index and runs from 1 to 3 in this case, right? What about b and c?

Yes and a, b and c can be 1, 2 or 3 giving 27 gamma's.

Mr-R said:
I am not sure how to use the metric connection. The indices confuse me.

You have to calculate all the gamma's, but a lot of them are equals or vanish.

Mr-R said:
Every time I try to calculate it I get zero, sometimes due to the first metric tensor and sometime the terms in the parentheses are zeros.

\Gamma_{bc}^{a}=\frac{1}{2}g^{ad}(\partial_{b}g_{dc}+\partial_{c}g_{db}-\partial_{d}g_{bc})

What did you find for the metric in these coordinates?
 
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I actually got it now :smile:

Thanks bloby
 
Ok, you're welcome.
 

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