Understanding Multivariable Calculus: Unpacking a Challenging Step

[name]

It has been a long time since i did multivariable calculus, i can't figure out how they get from the first line to the second (ignore the physics). Any ideas?

http://img517.imageshack.us/img517/5955/40978639pp5.th.jpg

Cheers,

 

[HallsofIvy]

It's a little hard to distinguish between $\nabla$ and V!
What you are asking is how they went from
$$\int\int\int (\nabla\cdot E)V d\tau$$
to
$$\int\int\int E\cdot\nabla V d\tau+ \int\int V (E\cdot dA)$$
(some people prefer $E\cdot n dA$ rather than $E\cdot dA$ where "n" is the unit normal to the surface.) V here is the scalar potential and E is a vector function.

There are actually two steps in there. First they are using the "product" rule:
[tex]\nabla\cdot(VE)= V\nabla\cdot E+ (\nabla V)\cdot E[/itex]<br /> where $\nabla\cdot E$ and $\nabla\cdot (VE)$ are the divergence (div) of the vectors and $\nabla V$ is grad V.<br /> <br /> so<br /> [tex]\int\int\int\nabla\cdot(VE)d\tau= \int\int\int V\nabla\cdot Ed\tau +\int\int\int(\nabla V)\cdot E d\tau[/itex]<br /> <br /> Now use the divergence theorem to convert that first integral on the right to<br /> [tex]\int\int VE\cdot dA[/itex]<br /> <br /> But I'm not at all clear why the $\epsilon_0/2$ only multiplies the first integral![/tex][/tex][/tex]