Understanding of Maxwell's Stress Tensor

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Discussion Overview

The discussion revolves around the Maxwell's stress tensor, particularly focusing on the interpretation of the squared electric and magnetic field terms within the tensor's formulation. Participants explore the mathematical representation and implications of these terms, seeking clarification on their meanings and calculations.

Discussion Character

  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • One participant questions what is meant by the squared electric and magnetic field terms in the stress tensor equation, specifically whether it refers to the magnitude of the net field squared.
  • Another participant clarifies that the squared terms represent the dot product of the vector field with itself, denoted as E^2 = \mathbf{E} \cdot \mathbf{E}.
  • Further elaboration is provided on the calculation of E^2, indicating it can be expressed as the sum of the squares of its components, {E^2} = {E_x}^2 + {E_y}^2 + {E_z}^2.
  • Participants express feelings of uncertainty or embarrassment about asking basic questions regarding tensors and their properties.

Areas of Agreement / Disagreement

There appears to be a general agreement on the interpretation of the squared terms as the dot product of the electric field vector with itself. However, the initial question about the nature of these terms indicates some uncertainty remains regarding the broader implications of the stress tensor.

Contextual Notes

Participants express uncertainty about the foundational aspects of tensors, which may indicate a need for further exploration of the underlying principles and definitions related to the stress tensor.

vwishndaetr
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Was a bit fuzzy as to whether this better fit HW or here, but since there really is no question associated with it, figured this made a bit more sense.

I have a couple basic questions about the stress tensor:

T_{ij} = \epsilon_0 \left( E_i E_j - \frac{1}{2} \delta_{ij} E^2 \right) + \frac{1}{\mu_0} \left( B_i B_j - \frac{1}{2} \delta_{ij} B^2 \right)

For the component electric and magnetic fields (denoted with "i" and "j" indices), they are what they are. What ever the indice at the time, that particular component fills it in. But for both the squared Electric and Magnetic Field terms, what is being squared? Is it the magnitude of the net field squared?

Might be a bit silly to be dealing with Tensors and asking such silly questions, but still want to know.

Thanks.
 
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It implicitly means the dot product of the vector field with itself.

E^2 = \mathbf{E}\cdot\mathbf{E}
 
Born2bwire said:
It implicitly means the dot product of the vector field with itself.

E^2 = \mathbf{E}\cdot\mathbf{E}

So it'd be,

{E^2} = \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2} \cdot \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2}

I feel so dumb asking this. Thanks again.
 
vwishndaetr said:
So it'd be,

{E^2} = \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2} \cdot \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2}

I feel so dumb asking this. Thanks again.

Or more simply just

{E^2} = {E_x}^2 + {E_y}^2 + {E_z}^2
 

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