Understanding of Maxwell's Stress Tensor

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SUMMARY

The discussion focuses on Maxwell's Stress Tensor, specifically the equation T_{ij} = \epsilon_0 (E_i E_j - \frac{1}{2} \delta_{ij} E^2) + \frac{1}{\mu_0} (B_i B_j - \frac{1}{2} \delta_{ij} B^2). Participants clarify that the squared terms E^2 and B^2 represent the dot product of the electric and magnetic fields with themselves, respectively. This means E^2 = E_x^2 + E_y^2 + E_z^2, confirming that the magnitude of the net field is being squared. The discussion emphasizes the importance of understanding tensor notation in electromagnetism.

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  • Understanding of Maxwell's equations
  • Familiarity with vector calculus
  • Knowledge of tensor notation
  • Basic concepts of electric and magnetic fields
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  • Study the derivation of Maxwell's Stress Tensor
  • Learn about the physical significance of the dot product in vector fields
  • Explore applications of Maxwell's Stress Tensor in electromagnetic theory
  • Investigate the relationship between electric and magnetic fields in different media
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Physicists, electrical engineers, and students studying electromagnetism who seek a deeper understanding of Maxwell's Stress Tensor and its implications in field theory.

vwishndaetr
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Was a bit fuzzy as to whether this better fit HW or here, but since there really is no question associated with it, figured this made a bit more sense.

I have a couple basic questions about the stress tensor:

T_{ij} = \epsilon_0 \left( E_i E_j - \frac{1}{2} \delta_{ij} E^2 \right) + \frac{1}{\mu_0} \left( B_i B_j - \frac{1}{2} \delta_{ij} B^2 \right)

For the component electric and magnetic fields (denoted with "i" and "j" indices), they are what they are. What ever the indice at the time, that particular component fills it in. But for both the squared Electric and Magnetic Field terms, what is being squared? Is it the magnitude of the net field squared?

Might be a bit silly to be dealing with Tensors and asking such silly questions, but still want to know.

Thanks.
 
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It implicitly means the dot product of the vector field with itself.

E^2 = \mathbf{E}\cdot\mathbf{E}
 
Born2bwire said:
It implicitly means the dot product of the vector field with itself.

E^2 = \mathbf{E}\cdot\mathbf{E}

So it'd be,

{E^2} = \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2} \cdot \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2}

I feel so dumb asking this. Thanks again.
 
vwishndaetr said:
So it'd be,

{E^2} = \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2} \cdot \sqrt {{E_x}^2 + {E_y}^2 + {E_z}^2}

I feel so dumb asking this. Thanks again.

Or more simply just

{E^2} = {E_x}^2 + {E_y}^2 + {E_z}^2
 

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