Understanding Phase Shift in Trigonometric Functions

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The phase shift of the function Y=-5sin(x-π/2) is π/2 units to the right, as indicated by the positive value of φ. In contrast, for the function y=4cos(x+π/2), the phase shift is also π/2, but it is to the left due to the positive sign in the equation. This creates confusion because a positive φ typically suggests a rightward shift, while a negative φ indicates a leftward shift. Clarification arises from understanding that the equation's structure can lead to different interpretations of φ. Ultimately, recognizing the signs in the context of the function's format is crucial for accurately determining phase shifts.
smashbrohamme
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Find the phase shift of a function.

Y=-5sin(x-pie/2)

The Phase shift is (pie/2)/1 which equals to pie/2. The correct answer is units to the right though..which is where I need clarification on.

My book said if phi is less than 0, it is too the left.. being -pie/2 wouldn't this indicate to the left?

Another example.

y=4cos(x+pie/2) once again phase shift is pie/2...but it is units to the left...units to left indicates phi...which is pie in this case..is negative...how is that possible?

It is easy to remember if it has a plus sign..it is units to the left...
negative sign ends up being units to the right...I just don't understand and if I don't truly understand than I won't remember it long term.

Thanks for your help.





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smashbrohamme said:
Find the phase shift of a function.

Y=-5sin(x-pie/2)

The Phase shift is (pie/2)/1 which equals to pie/2. The correct answer is units to the right though..which is where I need clarification on.

My book said if phi is less than 0, it is too the left.. being -pie/2 wouldn't this indicate to the left?

Another example.

y=4cos(x+pie/2) once again phase shift is pie/2...but it is units to the left...units to left indicates phi...which is pie in this case..is negative...how is that possible?

It is easy to remember if it has a plus sign..it is units to the left...
negative sign ends up being units to the right...I just don't understand and if I don't truly understand than I won't remember it long term.

Thanks for your help.
Does your book say something like:
For
\sin(x-\phi)\,,​
if \phi is positive then the shift is to the right,

if \phi is negative then the shift is to the left .​

?

If that's the case, then your \phi is π/2, which is positive.
 
ah, so they are factoring in that your equation sin(w-phi) can make two negatives into a positive...
 
smashbrohamme said:
ah, so they are factoring in that your equation sin(w-phi) can make two negatives into a positive...

Yes.
 
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