Understanding Power Output of a PSU

AI Thread Summary
The discussion centers on understanding the power output specifications of power supply units (PSUs), particularly what a rating like 750W signifies. It clarifies that this rating refers to the maximum power the PSU can deliver across various outputs, rather than a single voltage and current combination. The conversation also highlights the importance of knowing the load requirements for devices like function generators, which have specific preferred loads for optimal performance. Additionally, it emphasizes that the current draw from a load must not exceed the PSU's rated capacity to avoid damage. Understanding these parameters is crucial for safely operating electronic components and ensuring efficient power delivery.
D44
Messages
70
Reaction score
0
Hi

I'm just thinking over a few things and realized there's something pretty fundamental that doesn't seem to get explained often or at least very well. Maybe I'm too much of a novice, who knows...anyway...

When a power supply states a power output of say, 750W, what exactly does that mean? 750W when? Not when I'm supply something with 12V and 3A. So does it mean a maximum/combination/summation of outputs that the supply can handle before..it burns out?

For example, a psu, 750W output. This would happily supply several different components with different voltages and currents which add up to 750W. But what if there was just 1 output? Does that mean there could be an output of 375V and 2A? That doesn't seem right. But that's still 750W, right?
Also, when it comes to circuitry, things like frequency generators, how do you know what current they can handle? Because, for example, something like an induction coil/heater - dc signal into a function generator, to coil (I know there's more to it than that) - surely the high current drawn from the coil would be way too high for the function generator?
 
Engineering news on Phys.org
Power supplies are either fixed or variable. In either case, the power rating usually tells you how much current you can draw out of it at its max voltage, as opposed to how much power you can draw at a lower voltage.

So a variable supply rated at 10volts and 100 watts, and cranked up to the full 10 volts output, will put out 10 amps at 10 volts if you hook up a 1 ohm resistive load.

With a fixed supply, you don't have any choice on the voltage, so you can hook up any resistive load of 1ohm or more to a 10volt supply before you start to overload it.
 
Thanks for your reply, that's helpful.

So in the case of a function generator etc, how would you know what the limits of the circuit were, such as max curren they could handle? Would that be the input perameters?
 
A function generator typically has its preferred load marked on it, e.g., 10Ω
So with a 10Ω load, when you turn its amplitude up to near maximum, then it's delivering maximum power. :smile:

If you are talking about the control signals fed to the function generator, then those would be available in its user manual. They will be voltages, not watts.
 
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...
Back
Top