Understanding Real Gas Behavior: Deviations from Ideal Gas Equation

  • Thread starter Thread starter rumaithya
  • Start date Start date
  • Tags Tags
    Behavior
AI Thread Summary
Continuing to lower the temperature of a real gas, specifically an air mixture of nitrogen and oxygen, leads to significant deviations from ideal gas behavior at temperatures of 90 K and 77 K. These temperatures correspond to the boiling points of nitrogen and oxygen, respectively. As the temperature decreases, gas molecules transition from the vapor phase to the liquid phase, resulting in sudden drops in pressure. This phenomenon highlights the limitations of the ideal gas equation, particularly during phase changes, where the behavior of real gases diverges from theoretical predictions.
rumaithya
Messages
20
Reaction score
0
If you had continued to reduce the temperature of your real gas in this experiment (air mixture of mostly nitrogen and oxygen) to lower and lower temperatures, you would observe sudden drops in pressure at 90 K and 77 K. In other words, the behavior of the real gas would deviate significantly from the predicted straight-line behavior of the ideal gas equation determined in Question 3 and your extrapolated graph. Why ? [Hint: Consider what happens to water vapor(H2O(g)) when it is cooled to 0.0 C.]

Could anyone explain this, please ?
 
Chemistry news on Phys.org
Question 3

Where is this mysterious question 3...
 
Phase change

The temperatures 77 & 90 °K correspond to the liquefaction (boiling points) of Oxygen & Nitrogen respectively.

The pressure drops due to the removal of gas molecules from the vapour phase into the more condensed phase of liquid.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top