Understanding Simple Pendulum Experiment: Water-Filled Sphere Explanation

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In a simple pendulum experiment, the period of oscillation is influenced by the length of the pendulum and the distribution of mass. As water drains from a hollow sphere, the center of gravity shifts, initially causing the period to increase due to a longer effective length. Once the water level drops significantly, the center of gravity lowers, leading to a decrease in the period. The equation T=2pi(sqrt L/g) assumes all mass is concentrated at the bob, but adjustments are needed when considering the weight of the string and bob. Understanding these dynamics is crucial for accurately analyzing the pendulum's behavior.
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This is my first time ever taking a physics class...and needed an explanation. In lab we're doing a simple pendulum experiment. Given the equation T=2pi(sqrt L/g) and noting observations with different pendulum lengths we must then answer this question:

A hollow sphere is filled with water and suspended by a long thread. A small hole is made in the bottom of the sphere and as the water flows out one observes that the period of oscillation of the simple pendulum first increases and then decreases. Explain.
 
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The 'L' in the above equation is the length from the fixed end to the centre of gravity of the string+bob (the weight on the end of the string).
Where is the centre of gravity if the bob is much heavier than the string and where if the bob and the string have the same weight?

Slightly nasty question - the simple equation above normally assumes that all the weight is in the bob, there is a more complex equation if you need to take into account different weights.
 
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