Understanding Skeet Thrower Mechanics: Spring Selection and Release Velocity

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Discussion Overview

The discussion revolves around the mechanics of a DIY skeet thrower, focusing on the selection of springs and the relationship between spring energy storage, tension force from Hooke's law, and the release velocity of clay targets. Participants explore theoretical and practical aspects of machine dynamics related to this device.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about relating spring energy storage and tension force to the release velocity and angular velocity of the spring arm.
  • Another participant suggests that the question is fundamentally about machine dynamics and requests a schematic for better understanding.
  • A participant shares a link that may provide helpful information regarding spring selection.
  • Another participant proposes using conservation of energy to determine the release velocity, outlining steps to equate stored energy in the spring with kinetic energy at release.
  • One participant specifies a desired release velocity of approximately 15 m/s and provides the mass of the clay target as 0.12 kg.
  • Another participant inquires about the spring constants (k values) being considered and the expected amount of stretch in the spring when loaded.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the best approach to relate spring mechanics to the release velocity, and multiple viewpoints and methods are presented without resolution.

Contextual Notes

There are limitations regarding the assumptions made about energy transfer efficiency and the neglect of friction in the proposed calculations. Participants have not provided complete details on the spring specifications or dimensions of the device.

Cam_P
Hi guys!

I'm struggling to select a spring for a DIY skeet thrower i am making, it'll probably be a similar design to the one pictured.

I just don't understand how to relate the spring energy storage and the tension force from Hooke's law to the release velocity of the clay. or even the angular velocity of the spring arm.
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This is essentially a machine dynamics question, and should not be too difficult (I think). I'm not personally familiar with this device, so I'm not entirely clear as to what I'm seeing in the picture. Do you have a top view or a schematic showing clearly how the device works? If so, I'm pretty sure I can help you.
 
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this link may help

https://www.amazon.com/dp/B0714QHJ32/?tag=pfamazon01-20
 
https://outlook.office.com/owa/service.svc/s/GetFileAttachment?id=AAMkAGJiNGYzMzE2LTE2ZjctNDkwZS04YWU2LTFiZGNiNDZiNWExNABGAAAAAAAMsBEqZjKgS4Lp2EQQihiyBwBl1JHdDzN4S7H4NHxB29OKAAAAAAEMAABl1JHdDzN4S7H4NHxB29OKAAELotnqAAABEgAQAPHu44w2Xx9Gpbb%2BstqU2bw%3D&X-OWA-CANARY=rmkzbi613ESb6tabf406umDXG_7FFNUYjZegY9kXdkzDw3wdLWrlKiWqNFQngyKrC5VpkSAT5zA.&isImagePreview=True
 
Above is the sketch i have of the moving parts and relevant lengths
 
Cam_P said:
I just don't understand how to relate the spring energy storage and the tension force from Hooke's law to the release velocity of the clay. or even the angular velocity of the spring arm.
For a first cut, assume about 75% of the stored energy in the spring goes into the launch velocity of the pigeon. Do you know about what you want for the Vo of the pigeon? Then just use 1/2 mv^2 for the KE of the pigeon compared to 1/2 kx^2 for the PE stored in the taut spring.
 
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Cam_P said:
Above is the sketch i have of the moving parts and relevant lengths
Not working so far... Are you using the Upload button? What is the file type?
 
You ask about determining the release velocity. I suggest to you that the simplest approach is to employ conservation of energy.

1. Determine the energy stored in the spring with the system cocked.
2. Express the system energy at the point of release. This will include (a) the kinetic energy of the arm, (b) the kinetic energy of the clay, and (c) any remaining energy stored in the spring.
3. Set these two energies equal and solve for the final velocity.
This approach neglects friction, but that may not be too important in this application. The resulting velocity will be a little bit higher than actual for that reason.
 
I want the release velocity to be about 15ms-1
 
  • #10
What is the mass of the pigeon?
 
  • #11
0.12kg
 
  • #12
Well, what are the typical k values for the springs you are considering using? What is the amount of stretch you expect for your spring when in the loaded position.

Please show your work with the equations that Dr.D and I have been suggesting for you to use.
 
  • #13
I cannot see any sketch with dimensions; all I see is . I'd be very interested in seeing what you have designed here. In particular, I'd like to know what causes the actual launch to occur? Does the arm hit a stop, allowing the clay to continue on, or is it some other mechanism?

If you use the energy approach that I suggested, you can assign the release velocity and solve for the spring constant K, and you can play games with the free length of the spring (all in a simple computer code).

In addition to the mass of the clay, you will need the mass moment of inertia of the clay about the spin axis. A substantial part of the kinetic energy of the clay will reside in the spin, so this is an important term.
 

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