Understanding the Electron Configuration of Chromium: Explained [SOLVED]

AI Thread Summary
The discussion centers on the electron configuration of chromium, which has 24 electrons. The confusion arises from the expected configuration of 1s2, 2s2, 2p6, 3s2, 3p6, 3d6, which suggests filling the 3d subshell before moving to the 4s subshell. However, the actual configuration is 3d5, 4s1. This anomaly occurs because atoms tend to achieve greater stability when subshells are either fully filled or half filled. In chromium's case, one electron is removed from the 3d subshell to fill the 4s subshell, resulting in a half-filled 3d subshell and a half-filled 4s subshell, which reduces electron-electron repulsion and enhances stability. The conversation also references other elements with similar anomalous configurations.
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[SOLVED] Electron Configuration

Something in chemistry really has me perplexed. We are doing electron configuration stuff. I think I have a fairly good grip on it after I was able to let go of the Bohr Model.

My question is this. Chromium has 24 electrons which should fit into the first 3 shells 3s, 3p, 3d yet it uses the 4th shell. Why does it not fill up the third shell?

The way it seems it should be to me is 1s2,2s2,2p6,3s2,3p6,3d6 not 3d5,4s1



Thanks
 
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if i remember, the atom becomes more stable when a subshell is either fully filled/half filled. so with the 3d6 loses one electron to make it half full and places it in the 4s subshell to make that half filled as well making the atom more stable.
 
It does this to reduce electron-electron repulsion (making the atom more stable). There's a whole list of atoms with anomalous configurations, off the top of my head I can think of Cr, Cu, Nb, Mo, Ru, Rh, Ag, La, Ce, Pt, Au, Ac, Th, Pd. There are two or three more.
 
In the case of Cr, if it loses the one elctron to the 4s shell, that make 4s half full, but 3d is not half empty. At any rate, I think I see what you are saying.
Thanks
 
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