Understanding the Relativistic Velocity Equation

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SUMMARY

The discussion centers on the application of the relativistic velocity equation to calculate the velocity of a particle moving along the x' axis of frame S' with a velocity of 0.4c, while frame S' itself moves at 0.6c relative to frame S. The correct application of the equation u=(u' + v)/(1+u'v/c^2) reveals that the velocity of the particle with respect to frame S is 0.81c, not 1. The error arose from misunderstanding the units of measurement for velocity, specifically treating 'c' as a unit rather than a constant speed.

PREREQUISITES
  • Understanding of the relativistic velocity equation
  • Familiarity with the concept of frames of reference in physics
  • Knowledge of the speed of light as a constant (c)
  • Basic algebra skills for manipulating equations
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  • Explore examples of relativistic effects in particle physics
  • Learn about Lorentz transformations and their applications
  • Investigate the implications of special relativity on time dilation and length contraction
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of special relativity and the behavior of objects moving at relativistic speeds.

Lynny
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A particle moves along the x' axis of frame S' with velocity .4c. Frame S' moves with velocity .6c with respect to frame S. What is the velocity of the particle with respect to frame S'?

I used the realistic velocity equation:
u=(u' + v)/(1+u'v/c^2)

u=(.4 + .6)/(1+.4*.6/(3*10^8)^2)

The answer I get is 1 but the real answer is .81c

What am I doing wrong?

Thanks
 
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You are using u' = .4 and v = .6 instead of u' = .4c = .4*3*10^8 and v = .6c = .6*3*10^8.
 
I see. I keep thinking c is a unit of measurement. It all works now. Thanks!
 

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