Understanding the Role of Abelian Cartan Subalgebras in Simple Lie Algebras

  • Context: MHB 
  • Thread starter Thread starter topsquark
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the properties of simple Lie algebras, specifically A1 (or SL(2, ℂ)). It is established that A1 has an Abelian Cartan subalgebra, denoted as H, which is crucial for its structure. The confusion arises when considering E^{\pm} as potential Abelian Cartan subalgebras, leading to the incorrect conclusion that A1 could be decomposed into a direct sum of these elements. The conclusion drawn is that A1 cannot be represented as a direct sum of a Cartan subalgebra and its generators, confirming its classification as a simple Lie algebra rather than a semi-simple one.

PREREQUISITES
  • Understanding of simple Lie algebras, specifically A1 (SL(2, ℂ))
  • Familiarity with Abelian Cartan subalgebras
  • Knowledge of Cartan Weyl basis and Cartan matrices
  • Concept of isomorphism in the context of Lie algebras
NEXT STEPS
  • Study the structure and properties of simple Lie algebras
  • Explore the concept of Cartan subalgebras in depth
  • Learn about the classification of Lie algebras and their representations
  • Investigate the implications of root systems in Lie algebra theory
USEFUL FOR

Mathematicians, theoretical physicists, and students of algebraic structures who are focused on the study of Lie algebras and their applications in various fields.

topsquark
Science Advisor
Homework Helper
Insights Author
MHB
Messages
2,020
Reaction score
843
Say we have a simple Lie Algebra, and let's use A1: [math] [H, E^{\pm} ] = \pm 2 E^{\pm}[/math] and [math] [E^+, E^- ][/math] as an example. My text seems to be telling me that we can write this in a decomposition: [math] \{ H \} \oplus g[/math] as H is an (Abelian) Cartan subalgebra of A1.

My question is this: [math]E^{\pm}[/math] can individually be taken as Abelian Cartan subalgebras as well. That would make A1 isomorphic to [math]\{ H \} \oplus \{ E^+ \} \oplus \{ E^- \}[/math], which clearly isn't correct. How do we know to single out H for special treatment?

-Dan
 
Physics news on Phys.org
Okay. I finally finished my little project and I just can't see where the text is getting this. A1 (or [math]SL(2, \mathbb{C} )[/math], whichever you please, is clearly a simple Lie Algebra, not a semi-simple one. The text is working with a Cartan Weyl basis, Cartan matrix, root system, etc, all properties of a semi-simple Algebra as if A1 were semi-simple. After a long slog of picky details I finished working out a general basis for A1 and have finally proved that A1 is not isomorphic to the direct sum of a Cartan subalgebra and its other generators, and thus is not semi-simple.

So am I not understanding something (and going half-mad) or is the text wrong to do this?

-Dan
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K