Understanding the Second Order Relation of Entropy: A Homework Guide

thonwer
Messages
60
Reaction score
0

Homework Statement


Find:
%20%7B%5Cpartial%7BV%7D%5E%7B2%7D%7D%5Cright%29_%7BU%2Cn%7D&sig=0a98e71179d9121cbe9292db47132926.gif


Homework Equations


0%7BT%7D%20dV%20-%20%5Cfrac%20%7B%5Cmu%20%7D%20%7BT%7D%20dN&sig=9991a34d745d37dbf801cd5680dc06d4.gif

rac%7B%5Cpartial%20V%7D%20%7B%5Cpartial%20T%7D%5Cright%29_P&sig=915c3af3f202cfa1a71ec201be8bbe13.gif

5Cfrac%7B%5Cpartial%20V%7D%7B%5Cpartial%20P%7D%5Cright%29_T&sig=a8d6449c96e1bf7075a63641c3681184.gif

The Attempt at a Solution


_T%20T%7D-%5Cfrac%7BP%7D%7B%7BT%7D%5E%7B2%7D%5Calpha%20V%7D&sig=672f8542888eb9de5e60c442afe86b77.gif
 
Physics news on Phys.org
Have I done it in the right way? (I forgot to put the question :oops:)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top