Understanding Trigonometry: Explanation of the Inverse Tangent Function

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The discussion focuses on understanding the inverse tangent function and its application in trigonometry. A user seeks clarification on the relationship between the equation θ = tan^(-1)(x/2) and the expression -1/(4sinθ) = -√(x²+4)/(4x). The response emphasizes drawing a triangle with vertical side x and horizontal base 2 to apply the Pythagorean theorem for finding the hypotenuse. This approach allows for the calculation of csc(θ) directly from the triangle's sides. The user realizes the solution after posting, indicating a moment of clarity in their understanding.
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I have a straight-forward question. Could anybody please explain me why...

\theta = \tan ^{-1} \left( \frac{x}{2} \right) \Rightarrow -\frac{1}{4\sin \theta} = -\frac{\sqrt{x^2+4}}{4x}

Thanks
 
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Draw a triangle. Your vertical side will be x, your horizontal base will be 2. This is directly from the tan function. From there you can use pythagorean theorem to find the hypotenuse. Now you have all three sides, and you're trying to find

-4csc(\theta). Just pull it right off the triangle. CSC is hyp/opp.
 
One sec. after I posted it I realized what to do. Thanks, anyway.
 
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