Understanding Vector Equations and Their Significance in Mathematics

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Homework Statement


What is the significance of each vector forumula? Which one is used for what and why? What is the purpose of the symmetric function?

Homework Equations


1) r = r0 + tv
2) r(t) = (1 - t)r0 + tr1
3) Symmetric equation

The Attempt at a Solution


My textbook introduced me to the first formula write equations for vectors, which I understand. Later it introduced segments and modified the first equation to the second one, without any clear explanation. I don't understand why separate formulas are needed for vectors and segments. Finally, my textbook concluded that chapter by eliminating the parameter t and getting the "symmetric equation". What is the purpose of that equation? Thank you so much. This is so confusing for me.
 
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The first one describes a particle at position r0 at time t0=0 moving with velocity v. The r then is the position at any time t of the particle.

The second one is saying given a particle at r0 and then at r1 you can determine its position at any time t.

Notice when you rearrange the terms a bit you get r0 + (r1 - r0) t so the (r1 - r0) factor is the velocity v from the first equation.

I'm not sure about the symmetric equation...
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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