Understanding Vector Equations in Homework Problems

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The discussion focuses on understanding vector equations in homework problems, specifically regarding the interpretation of red and blue equations. The red equation is identified as a unit vector in both vector and scalar formats, while the blue equation relates to the dot product and cross product. Participants clarify that for the cross product (del X F) to equal zero, certain conditions must be met, specifically that delyFz equals delzFy. The conversation also touches on the implications of differentiating the equations and how signs affect the results. Overall, the thread provides insights into the mathematical relationships and rules governing vector calculus.
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Homework Statement


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Homework Equations


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The Attempt at a Solution



can anyone enlighten me what the red and blue equations mean? i remembered something about the red eqn meaning unit vector in vector format, or scalar format is it?

and the blue eqn i have totally no idea what my prof is doing >< is he trying to say that del F is a dot product and since they are 0 because i =/= j, that means that cross product is 0?

help appreciated!
 
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hi quietrain ! :smile:

it's all very simple …

r^/r2 = (r/|r|)/r2 = r/r3

and

∂/∂xi (Fj)

= ∂/∂xi (xj)

= ∂/∂xi (xj/r3)

= {∂/∂xi (xj)}/r3 + {∂/∂xi 1/r3)}xj (product rule)

= 0 + {∂/∂xi 1/r3)}xj :wink:
 
with regards to part b)

for the cross product (del X F) to be 0, are they saying that delyFz - delzFy must be 0 and the other permutations too,

so that delyFz = delzFy

but from the form ∂/∂xi (Fj), it has a minus sign after differientiating, thus for Eijk, if we swop once to Eikj , then the minus sign is gone

so now its minus - plus = 2 minus , not 0?
 
hi quietrain! :smile:

(have a del: ∇ and an epsilon: ε :wink:)
quietrain said:
for the cross product (del X F) to be 0, are they saying that delyFz - delzFy must be 0 and the other permutations too,

so that delyFz = delzFy

yes :smile:
but from the form ∂/∂xi (Fj), it has a minus sign after differientiating, thus for Eijk, if we swop once to Eikj , then the minus sign is gone

so now its minus - plus = 2 minus , not 0?

ah, you can either write ∇jFk - ∇kFj

or εijkjFk

same thing :wink:
 
tiny-tim said:
hi quietrain! :smile:

(have a del: ∇ and an epsilon: ε :wink:)


yes :smile:


ah, you can either write ∇jFk - ∇kFj

or εijkjFk

same thing :wink:


oh so it becomes minus minus minus which is minus plus = 0
thanks!
 
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