Understanding Voltage in a Simple Circuit: A Quick Question

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The discussion focuses on understanding voltage in simple circuits, specifically regarding voltage drops across resistors and inductors. The initial question confirms that the voltage drop from point A to B (v(t)) is indeed the voltage across resistor R2. The conversation then shifts to a new circuit configuration, where participants clarify that the voltage drop from A to B is the sum of the voltages across R1 and the inductor or R2. There is confusion about current division between the inductor and R2, which is resolved by confirming that they share the same voltage drop. Overall, the thread emphasizes the application of Kirchhoff's Voltage Law (KVL) in analyzing circuit behavior.
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Hi all, I am asking to see if I understand voltage correctly:
This is what circuit looks like:
Code:
-----R1---A----R2---
|           +      |
Vs         v(t)    |
|           -      |
|_________B_______ |
As I see it, v(t)(voltage drop from A to B) is voltage across R2, is it correct?
Thank in advance.
 
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that is correct
 
What? the sum of the voltage drop from R1 and R2 is equal to the EMF (battery).
 
Didn't want to start another thread, but now I have another question: after the switch in some circuit moves to a certain position I get following circuit:
Code:
 A-------R1--------------
                |        |
                |        |
             indctr     R2
                |        |
                |        |
 B-----------------------
Then voltage drop from A to B is sum of voltages across R1 and inductor (or R2), right? Then there is a current coming from A and divides into 2 (for inductor and R2)? Or does R1 not have any current?
Thanks again.
 
Last edited:
drop from A to B is Vr1 and 2*Vr2. Even though the inductor and r2 voltages are the same, they both must be added.
 
Why 2*VR2? they are in parallel. What am I missing here? Don't inductor and R2 follow KVL?
 
oops, my bad. youre right. its just one.
 
Oh, Ok, thanks!
 
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