Engineering Understanding Z(in) of Circuit: A, B, C, D Explained [No Frequency Given]

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The discussion focuses on calculating the input impedance Z(in) of a circuit without a given frequency. Participants clarify that the problem implies using j2 as the frequency, leading to the conclusion that ω = 2 rad/s. They emphasize the need to express the impedance in the form Z(jω) and substitute the value of ω accordingly. The correct interpretation of the transfer function H(jω) is also highlighted, indicating that V(j2) represents the voltage in the frequency domain. Ultimately, the key takeaway is that understanding the relationship between impedance and frequency is crucial for solving the problem.
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Z(in) of circuit help??

Homework Statement


qq2wl0.png

A. 10+j2.5 (Ω)
B. 10-j0.4 (Ω)
C. 10-j2.5 (Ω)
D. 10+j0.4 (Ω)

Homework Equations


Z(L)=jwl
Z(C)=-j/wc

The Attempt at a Solution


the problem asks for z(in) without any frequency w given? i think i was just confused by the wording of this problem. s=sigma+jw so does that mean, j2 given means w=2?? then answer would be 10+j2.5 (A). but I'm unsure how to do this without any w.
 
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Yeah, it looks like they are asking for Z(w=j2), so j2 must be the frequency w. 2Hz shifted by 90 degrees...?
 
Remember your transfer function can be expressed in the form H(jω) = Vo(jω)/Vi(jω), where we can denote jω by s.

Here you are trying to find the input impedance Z(i), or in other words Z(jω), where Z(jω) = Z(2j).

So you can conclude that ω = 2 rad/s or ω = 2*pi*f = 2 and find the frequency.

Find the total impedance of the system and substitute your value of ω.
 
The general expression is V(s). To express in the frequency domain, we simply substitute s with , giving V(jω)

So V(j2) indicates V(jω) with ω=2 radians/sec.
 

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