Undetermined Coefficients, more than one term on RHS

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Homework Help Overview

The problem involves solving a differential equation of the form y'' - 49y = 7cos(7x) + 7 + e^(7x), which includes multiple terms on the right-hand side. The subject area is differential equations, specifically focusing on the method of undetermined coefficients.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find a particular solution after determining the homogeneous solution but expresses confusion regarding how to handle multiple terms on the right-hand side. Some participants suggest that the particular solution can be constructed by summing the contributions from each term individually.

Discussion Status

Participants have provided guidance on how to approach the problem by indicating that the particular solution can be formed by adding the individual solutions for each term on the right-hand side. There is acknowledgment of the need to modify the particular solution due to the presence of a root in the auxiliary equation, but no consensus has been reached on the complete method.

Contextual Notes

There is a mention of the auxiliary equation and the need to adjust the particular solution because of the term '7' appearing as a root, indicating potential complications in the solution process.

Linday12
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Homework Statement


y''-49y=7cos(7x)+7+e^(7x)


The Attempt at a Solution


I have no idea how to solve this Differential equation. I could solve one that has y''-49y=one term, but I'm stumped with more than one.

First, I get the homogeneous equation, y''-49y=0 and fine y_c, then use the formulas to get y_p, but that is where I'm stumped, since I'm not sure how to find it with the 3 terms on the R.H.S.
 
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You just add the yp]'s for the individual functions.

For example, if your RHS was ex+cosx, your yp would be
yp=Aex+Bcosx+Csinx.
 
Awesome. That sounds like exactly what I needed to know. Thanks!
 
for more than one term on the right hand side you just sum up the result. i.e for 7cos(7x)
yp=Acos(wx)+Bsin(wx). for 7 yp=C and for e^(7x) yp=De^(\lambdax)
using sum rule yp=Acos(wx)+Bsin(wx)+C+De^(\lambdax)

edit: guess rock beat me to it
 
Linday12 said:
Awesome. That sounds like exactly what I needed to know. Thanks!

Just be sure to note that you will have to modify your yp a bit, since '7' appears as a root in your auxiliary equation.
 

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