Uniform ladder on a frictionless wall?

AI Thread Summary
To solve the problem of a uniform ladder resting against a frictionless wall, start by drawing a detailed diagram that labels all forces acting on the ladder. Apply the conditions for equilibrium, which include balancing the forces and moments acting on the ladder. Calculate the normal force at the base and the frictional force using the coefficient of static friction provided. This approach will help determine the reactions on both sides of the ladder effectively. Understanding these principles is crucial for accurately solving the problem.
honestliar
Messages
6
Reaction score
0

Homework Statement



An 8.00m uniform ladder whose mass is 55 kg is resting against a frictionless wall. Its lower end is 750cm from the wall. If the coefficient of static friction between the floor and the lower end of the ladder is 0.60, calculate the reactions on both side of the ladder.

Any help please?
 
Physics news on Phys.org
What have you done so far?

Start by drawing a diagram of the ladder with every force labeled. Then apply the conditions for equilibrium.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top