Unit Step Function Homework: Solve f(t) for t = -1

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Homework Statement


I'm having a bit of difficulty understanding the unit step function
For example
f(t) = 6u(-t) + 6u(t+1) - 3u(t+2)
t = -1


Homework Equations





The Attempt at a Solution



If t = -1 then the way I would do the problem is say that if u(t) returns a negative number or zero then it's zero
6(1) + 6u(0) - 3(1) = 3
However, the answer is 9 so I must be misinterpreting how the unit step function works. Can anyone explain to me how one would handle the unit step function in this situation?
 
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The unit step function, u(x) is 1 at x=0, not 0. This is your problem. Try evaluating you expression, taking this into account, and you should get 9 as your answer.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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