Engineering Unity gain in lowpass STC circuit

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In a low pass Single Time Constant (STC) circuit, the gain reaches 0dB at a frequency of 10^8 Hz, calculated from the 3dB frequency of 10^6 Hz, where the gain decreases at a rate of -20dB per decade. The confusion arises from the interpretation of the gain graph, which shows that the gain starts at 40dB (100 V/V) and remains at that level until the 3dB frequency is reached. After this point, the gain begins to attenuate at the specified rate. Understanding the log scale is crucial, as it indicates that the gain does not start decreasing until after the 3dB frequency. Thus, the initial gain is determined by the DC gain value before it begins to drop.
gambit1414
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One of the question asks to find the frequency at which the gain becomes 0dB for a low pass Single Time Constant circuit. In the solution manual after finding the 3dB frequency = 10^6, it states that since the gain falls off at a rate of -20dB/dec (see attatchment for graph) starting at w0(Omega-knot) , which is 10^6, the gain will reach 0dB in 2 decades (a factor of 100), therefore unity gain frequency = (10^6)(10^2)= 10^8. Now i don't understand how the gain will reach 0dB in 2 decades, because if you look at the graph of a low pass stc circuit it starts off at 0dB then falls by -20dB/dec. Am i reading the log scale graphs incorrectly? Please clarify. Thank You.
 

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Sorry, the dc gain (K) is also given which is 100 V/V = 40dB, so it seems like the gain should be 40dB until w=w0 (omega = omega-knot), then the gain starts to attenuate at -20dB/dec. I'm not really good at reading the log graphs so does this mean depending on what your dc gain value is, it will start there and then start decreasing at -20dB/dec after 3dB frequency? Thanks Again.
 
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