Unsure about formula for kinetic energy

AI Thread Summary
The discussion centers on the application of the kinetic energy formula mg*l*sin(theta) in the context of a falling flagpole and ball. Participants clarify that the formula is valid only if the mass of the pole is negligible and the ball's diameter is significantly smaller than the pole's length. The velocity vector is determined to be perpendicular to the pole, not tangential. There is a critique of the problem's formulation, questioning its validity and expressing discontent over the depiction of the flag. Ultimately, the conversation emphasizes the need for careful consideration of the variables involved in the physics problem.
Warlic
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Imagine the flagpole and ball with mass m fall together. Can I here use the formula mg*l*sin(theta)=(1/2)*mv^2
If I can, in what direction will the velocity vector be - is it going to be tangential to the flagpole?
 
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You can use the formula, if

1) the mass of the pole can be neglected and
2) the diameter of the ball is much smaller than the length of the pole.

The velocity vector would be perpendicular to the pole (but I think that's what you ment).
 
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stockzahn said:
You can use the formula, if

1) the mass of the pole can be neglected and
2) the diameter of the ball is much smaller than the length of the pole.

The velocity vector would be perpendicular to the pole (but I think that's what you ment).
"the diameter of the ball is much smaller than the length of the pole."
Why is this?
 
Your equation is incorrect. What does it tell you when theta is zero? Try again.

Also, what idiot made up this problem. The US flag should never be shown disrespectfully falling down!

Chet
 
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For the same reason as discussed yesterday. This formula couldn't be applied for the pole because each slice dm moves with a different velocity depending on the position. If the diameter of the ball would have a similar value as the length of the stick, then you would have to take the different slices of the ball into account. If the stick is much longr, than you can consider all slices of the ball moving with the same velocity.
 
stockzahn said:
For the same reason as discussed yesterday. This formula couldn't be applied for the pole because each slice dm moves with a different velocity depending on the position. If the diameter of the ball would have a similar value as the length of the stick, then you would have to take the different slices of the ball into account. If the stick is much longr, than you can consider all slices of the ball moving with the same velocity.
Alright, thank you, I think I get the idea now
 
Chestermiller said:
Your equation is incorrect. What does it tell you when theta is zero? Try again.

Also, what idiot made up this problem. The US flag should never be shown disrespectfully falling down!

Chet
It tells me there is zero potential energy at that point, everything is turned into kinetic energy?
 
Warlic said:
It tells me there is zero potential energy at that point, everything is turned into kinetic energy?
According to your equation, the velocity is zero when theta is equal to zero.
 
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