Find the maximum frequency for which the block and piston will be in contact

AI Thread Summary
The block and piston will separate when the piston's amplitude equals the height of the block, which occurs at a period of 1.18 seconds. The acceleration of the piston must equal gravitational acceleration for separation to happen. The maximum frequency for continuous contact between the block and piston can be calculated using the formula f = 1/T, yielding a maximum frequency of 0.8475 Hz. This frequency ensures that the block remains in contact with the piston throughout its motion. Understanding these dynamics is crucial for analyzing simple harmonic motion in this context.
radtad
Messages
19
Reaction score
0
A block is on a piston that is moving vertically with simple harmonic motion. a)At what amplitude of motion will the block and piston sperate if the period of the piston's motion is 1.18 seconds? b) If the piston has an amplitude of 5.12 cm in its motion, find the maximum frequency for which the block and piston will be in contact continuously.
 
Physics news on Phys.org
radtad said:
A block is on a piston that is moving vertically with simple harmonic motion. a)At what amplitude of motion will the block and piston sperate if the period of the piston's motion is 1.18 seconds? b) If the piston has an amplitude of 5.12 cm in its motion, find the maximum frequency for which the block and piston will be in contact continuously.

a) The block and piston will separate when the force of the piston(assuming it is constant) equals the Force of gravity. So you know the acceleration of the piston must be 'g'... I assume the amplitude of the motion is the distance traveled in 1/4 of the period.

b)Although I said the acceleration must be 'g' to seperate, we can also use it for the max frequency for the block and piston to remain in contact. Basically just work backward except frequency = 1/T
 


a) The block and piston will separate when the amplitude of the piston's motion is equal to the height of the block. Therefore, the amplitude of the piston's motion at which the block and piston will separate is 1.18 seconds.

b) The maximum frequency for which the block and piston will be in contact continuously can be found by using the formula for simple harmonic motion: f = 1/T, where T is the period of motion. Since we know that the period of the piston's motion is 1.18 seconds, the maximum frequency can be calculated as f = 1/1.18 = 0.8475 Hz. Therefore, the maximum frequency for which the block and piston will be in contact continuously is 0.8475 Hz.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top